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(B) The reaction is an electrophilic addition of $HBr$ to an alkene. $1$. The proton $(H^+)$ from $HBr$ attacks the double bond to form the most stabl

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$1-$bromo$-1-$isopropylcyclopentane

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(B) The reaction is an electrophilic addition of $HBr$ to an alkene. $1$. The proton $(H^+)$ from $HBr$ attacks the double bond to form the most stable carbocation. $2$. The alkene is $1$-isopropylcyclopentene. $3$. Protonation at the $C_2$ position (the carbon without the isopropyl group) creates a tertiary carbocation at the $C_1$ position,which is stabilized by the isopropyl group and the ring. $4$. The bromide ion $(Br^-)$ then attacks this tertiary carbocation to form $1$-bromo-$1$-isopropylcyclopentane. $5$. This follows Markovnikov's rule,where the nucleophile $(Br^-)$ attaches to the more substituted carbon.

Which of the following is the major product in the following reaction?

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